-x^2+40x=500

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Solution for -x^2+40x=500 equation:


Simplifying
-1x2 + 40x = 500

Reorder the terms:
40x + -1x2 = 500

Solving
40x + -1x2 = 500

Solving for variable 'x'.

Reorder the terms:
-500 + 40x + -1x2 = 500 + -500

Combine like terms: 500 + -500 = 0
-500 + 40x + -1x2 = 0

Begin completing the square.  Divide all terms by
-1 the coefficient of the squared term: 

Divide each side by '-1'.
500 + -40x + x2 = 0

Move the constant term to the right:

Add '-500' to each side of the equation.
500 + -40x + -500 + x2 = 0 + -500

Reorder the terms:
500 + -500 + -40x + x2 = 0 + -500

Combine like terms: 500 + -500 = 0
0 + -40x + x2 = 0 + -500
-40x + x2 = 0 + -500

Combine like terms: 0 + -500 = -500
-40x + x2 = -500

The x term is -40x.  Take half its coefficient (-20).
Square it (400) and add it to both sides.

Add '400' to each side of the equation.
-40x + 400 + x2 = -500 + 400

Reorder the terms:
400 + -40x + x2 = -500 + 400

Combine like terms: -500 + 400 = -100
400 + -40x + x2 = -100

Factor a perfect square on the left side:
(x + -20)(x + -20) = -100

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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